Question

Y=(x^2+x+1)*(x^2-x+1) Найти производную функции

Answer 1

$y=(x^2+x+1)(x^2-x+1)\\\\y'=(x^2+x+1)'(x^2-x+1)+(x^2+x+1)(x^2-x+1)'\\\\y'=(2x+1)(x^2-x+1)+(x^2+x+1)(2x-1)=\\\\=2x^3-\underline{2x^2}+2x+\underline{x^2}-x+1+2x^3-\underline{x^2}+\underline{2x^2}-x+2x-1=\\\\=\boxed{4x^3+2x}$