Так как √48=√16×3=4√3,
то числа равны:
4√3=4√3.
<span>7ax^5*(-2a^4x)=<span>-14a^5x^6</span></span>
1)
(2x - 9)(x + 6) - x(x + 6) = 0
(x+6)(2x-9-x)=0
(x+6)(x-9)=0
x+6=0 x-9=0
x= - 6 x=9
2)
(8x+ 4)(x - 10) + (10 - x)(x - 8) = 0
(8x+ 4)(x - 10) - (x - 10)(x - 8) = 0
(x-10)(8x+4-x+8)=0
(x-10)(7x+12)=0
x-10=0 7x+12=0
x=10 7x= - 12 /:7
x= - 12/7