(a1+d)(a1+3d)=-5
a1+4d-a1-2d=-6⇒2d=-6⇒d--3
(a1-3)(a1-9)=-5
a1²-9a1-3a1+27+5=0
a1²-12a1+32=0
a1(1)+a1(2)=12 U a1(1)*a1(2)=32
a1=4 или a1=8
Ответ:
√8·√50=2√2·5√2=10·(√2)²=10·2=20.
Объяснение:
1
3a²-1/4*ax-4a+5a³x
2
-6a^4b²+8a³b^5
3
5a²b³(3b^4-4a)
4
(x-y)(6ab^5+15a³b²)=3ab²(x-y)(2b³+5a²)
5
27x³y³-9x^4y-3xy³+9x5+9x^4y=27x³y³-3xy³+9x^5