1.Ca(OH)2+2HCl=CaCl2+2H2O
2.KOH+ HCl= KCl+ H2O
3.Cu(OH)2+ H2SO4= CuSO4+ 2H2O
4.Na2SO4+Cu(NO3)2=CuSO4+2NaNO3
5.H2SO4+Al= H2+ Al2(SO4)3
6.2H3PO4+3Ca= Ca3(PO4)2+3H2
7.P2O5+3H2O = 2H3PO4
8.2H2O=2H2+ 2O
9.Na+Cl=NaCl
10.NaNO3 = (t) 2 NaNO2 + O2
.............................
CH3COOK + H2O ===> CH3COOH + KOH
CH3COOH + СH3OH ===> CH3COOCH3 + H2O
2CH3COOCH3 + 7O2 ===> 4CO2 +6H2O
Дано
m(NaOH)=40 g
m(AlCL3)=40 g
--------------------
m(Al(OH)3-?
40 40.05 xg
3NaOH+AlCL3-->Al(OH)3+3NaCL
3*40 133.5 78
M(NaOH)=40 g/mol
M(AlCL3)=133.5 g/mol
M(Al(OH)3=78 g/mol
n(NaOH)=m/M=40/40=1 mol
n(ALCL3)=m/M=40.05/133.5=0.3 mol
n(NaOH)>n(ALCL3)
40.05/133.5 = X/78
X=23.4 g
ответ 23.4 г
Ответ:
Объяснение:
BaCO3 -> BaO + CO2 ( разложение)
N2 + 3H2 = 2NH3 (соединение)
Fe + 2HCl = FeCl2 + H2 ( замещение)
SO3 + H2O = H2SO4(соединение)