x² + y² = 2xy + 5x
x² - 2xy + y² = 5x
(x-y)² = 5x
10² = 5x
100= 5x
x = 20
y = x - 10 = 20 - 10 = 10.
Ответ: (20;10).
F '(x)=<span>4x^3-x^2
</span>f(x)=x⁴-x³/3+C
(19*√(13/19)-13*√(19/13)<span>)^2=(√19^2*13/19- √13^2*19/13)^2=(√361*13/19-√169*19/13)^2=(√247-√247)^2=0^2=0</span>
4/7(-9.27)-4/7(-2.27)=4/7(-9.27-(-2.27))=4/7(-9.27+2.27)=<span>4/7</span>·(-7)=-4