F'(x) = 2*1/2*x^(-1/2)=1/x^(1/2)=
1/16^(1/2)= 1/4
Ответ: С
1)(1/3*a^2*b)^3*(9ab^2)^2=(1/27*a^6*b^3)(81a^2*b^4)=3a^8*b^7
2)(-5a^3*b)^2*(1/5*a*b^3)^3=(25a^6*b^2)*(1/125*a^3*b^9)=1/5*a^9*b^11
3)(-2/7a*b^4)^2*(-3 1/2a^3*b)^2=(4/49a^2*b^8)(49/4*a^6*b^2)=a^8*b^10
Б.
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Tg 5x = √3;
5x = arctg(√3) + πk; k ∈ Z;
x = (arctg(√3) + πk)/5; k ∈ Z;
x = (π/3)/5 + (πk)/5; k ∈ Z;
x = π/15 + (πk)/5; k ∈ Z;