Question

A) 5^4x - 25^x+3 < 0 B) 0.2^x-5 - 0.04^x > 0 Найти х, заранее спасибо

Answer 1

$5^{4x}-25^{x+3}\ \textless \ 0\\\\ 25^{2x}\ \textless \ 25^{x+3}\\\\ 2x\ \textless \ x+3\\\\ 2x-x\ \textless \ 3\\\\ x\ \textless \ 3\\\\ x\in(-\infty; 3)$


$0.2{x-5}-0.04^x\\\\ 0.2^{x-5}\ \textgreater \ 0.2^{2x}\\\\ x-5\ \textless \ 2x\\\\ x-2x\ \textless \ 5\\\\ -x\ \textless \ 5\\\\ x\ \textgreater \ -5\\\\ x\in(-5;+\infty)$