Question

Помогите решить ремень срочно

Answer 1

$(3-5x)(2x+4)+8 x^{2} =-4x \\ 6x+12-10 x^{2} -20x+8 x^{2} +4x=0 \\ -2 x^{2} -10x+12=0\\2 x^{2} +10x-12=0/:2\\ x^{2} +5x-6=0\\D=25+24=49 \\ \sqrt{D} =7 \\ x_{1} = \frac{-5+7}{2} =1 \\ x_{2} = \frac{-5-7}{2} =-6$

Answer 2

$(3-5x)(2x+4)+8 x^{2} =-4x$
$6x+12-10 x^{2} -20x+8 x^{2} +4x=0$
$-2 x^{2} -10x+12=0$
$x^{2} +5x-6=0$
$D=25+24=49$
$x_1=1$
$x_2=-6$
Ответ: - 6 ; 1