Question

СРОЧНОООО
17БАЛЛООВВ
МАТЕМАТИКА

Answer 1

∠AOB+∠BOC+∠AOC=360°
∠AOC+220°=360°
∠AOC=360°-220°
∠AOC=140°

∠BOC+140°=290°
∠BOC=290°-140°
∠BOC=150°

∠AOB+150°=220°
∠AOB=220°-150°
∠AOB=70°
Ответ: ∠AOB=70° , ∠BOC=150° , ∠AOC=140°.