Question

1) 25,2:3 1\2+(6-4 1\3)*0,6= 2)(7-1 5\12):6,7+(5,75-3 1\6):15,5 = Помогите....

Answer 1

$1) \\ \frac{126}{5} \div \frac{7}{2} + (6 - \frac{13}{3} ) \times \frac{3}{5} = \frac{126}{5} \times \frac{2}{7} + \frac{5}{3} \times \frac{3}{5} = \frac{18}{5} \times 2 + 1 = \frac{36}{5} + 1 = 8.2 \\ \\ 2)$

(7-17/12):67/10+(23/4-19/6):31/2=67/12*10/67+31/12*2/31=1/6*5+1/6=5/6+1/6=1

Answer 2

$1)~25,2:3 \dfrac{1}{2}+(6-4 \dfrac{1}{3})\cdot 0,6=\\ \\=25,2:3,5+(5\dfrac{3}{3}-4\dfrac{1}{3})\cdot 0,6=\\ \\ =252:35+1\dfrac{2}{3}\cdot \dfrac{6}{10}=\\ \\=7,2+\dfrac{5}{3}\cdot \dfrac{3}{5}=7,2+1=\boldsymbol{8,2}$

$2)~\Big(7-1 \dfrac{5}{12}\Big):6,7+\Big(5,75-3 \dfrac{1}{6}\Big):15,5 =\\ \\ =\Big(\dfrac{84}{12}-\dfrac{17}{12}\Big):\dfrac{67}{10}+\Big(\dfrac{575}{100}-\dfrac{19}{6} \Big) :\dfrac{155}{10} =\\ \\=\dfrac{67}{12}\cdot\dfrac{10}{67}+\Big(\dfrac{23}{4}-\dfrac{19}{6} \Big):\dfrac{31}{2}=\\ \\ =\dfrac{5}{6}+\Big(\dfrac{69}{12}-\dfrac{38}{12} \Big)\cdot \dfrac{2}{31}=\dfrac{5}{6}+\dfrac{31}{12}\cdot \dfrac{2}{31}=\\ \\ =\dfrac{5}{6}+\dfrac{1}{6}=\dfrac{6}{6}=\boldsymbol{1}$