d = 8 м; S — ? Решение: d = 2r; r = d : 2; r = 8 : 2 = 4 (м) — радиус юрты; S = п * r^2 = 3,14 * 4^2 = 3,14 * 16 = 50,24 (м^2) —площадь
19/32+27/32=46/32=1 14/32
11/18+3/5=55/90+54/90=109/90=1 19/90
5/8+13/28=35/56+26/28=61/28=2 5/28
5/8+41/56=35/56+41/56=76/56=1 20/56=1 5/14
15/46+21/23=15/46+42/46=57/46=1 11/46
7/10+5/9=63/90+50/90=113/90=1 23/90
5/9+23/90=50/90+23/90=73/90
7/12+25/48=28/48+25/48=53/48
Утверждение неверно.
![\int\limits^-_- {\frac{-dcosx}{\sqrt{1+2cosx}}} \,](https://tex.z-dn.net/?f=+%5Cint%5Climits%5E-_-+%7B%5Cfrac%7B-dcosx%7D%7B%5Csqrt%7B1%2B2cosx%7D%7D%7D+%5C%2C%C2%A0+)
Cosx=t
= - (1+2t)^(1/2) *(1/2) / (1/2) +C=
- (1+2t)^(1/2) +C= - √(1+2cosx) +C