Question

3×(1/3)^2 -1= 1/4-2×3= (6/-4 )+3= (-1/3)^2 -3×(-1/3)+1= 3-cos0/2= 3-cos (п/3)/2= 3-cos (-п)/2=

Answer 1

1)3*(1/3)²-1=3*1/9-1=1/3-1=-2/3
2)1/4-2*3=1/4-6=-5 3/4
3)6:(-4)+3=-1,5+3=1,5
4)(-1/3)²-3*(-1/3)+1=1/9+1+1=2 1/9
5)3-cos0/2=3-1=2    (если (3-cos0)/2=(3-1)/2=1)
6)3-cos(π/3)/2=3-cos(π/6)=3-√3/2  (если (3-cos(π/3))/2=(3-0,5)/2=1,25)
7)3-cos(-π)/2=3-0=3 (если (3-сos(-π))/2=(3+1)/2=2)