Question

Найти предел,не используя правило Лопиталя (6x^2 + x -1)/(x-1/3) x->1/3

Answer 1

$\lim_{x \to 1/3} \frac{6x^2+x-1}{x-1/3}= \lim_{x \to 1/3} \frac{6(x-1/3)(x+1/2)}{x-1/3}= 6\lim_{x \to 1/3} (x+1/2)=5$