Question

(х+4)(х-4)-(2х-3)^2=-2х(х+1)-22помогите пж дам 100 балов срочно

Answer 1

(х+4)(х-4) - (2х-3)² = -2х(х+1) - 22,
х² - 16 - 4х² + 12х - 9 = -2х² - 2х - 22,
х² - 16 - 4х² + 12х - 9 + 2х² + 2х + 22 = 0,
-х² + 14х - 4 = 0,
Д = 14² - 4*(-1)-(-4) = 196 - 16 = 180,
х1 = (-14 - 6√5) / -2 = 7 + 3√5,
х2 = (-14 + 6√5) / -2 = 7 - 3√5