Question

F(x)=3/(5-x) + x^2/5 найти f'(2)

Answer 1

$f'(x) = -\frac{3}{(5-x)^2} + \frac{2x}{5} \\ f'(2) = - \frac{3}{9} + \frac{4}{5} = \frac{36-15}{45} = \frac{21}{45} = \frac{7}{15}$

Answer 2

Фото///////////////////////////////////////////////////