Question

Найти корень уравнения log2(7-x)=5

Answer 1

$log_{2} (7-x)=log_{2} 2^{5} => \left \{ {{7-x>0} \atop {7-x= 2^{5} }} \right. => \left \{ {{x<7} \atop {x=-25}} \right.$.Откуда х=-25