2Fe + 6HCl = 2FeCl3 + 3H2
FeCl3 + 3KOH = Fe(OH)3 + 3KCl
2Fe(OH)3 = (t°) Fe2O3 + 3H2O
Решение в файле
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2Ag+2H2SO4=Ag2SO4+SO2+2H20
n(SO2)=5.6л/22.4=0.25моль
2n(SO2)=n(Ag)=0.25*2=0.5 моль
m(Ag)=0.5моль*108=54г
<span>1)<span> </span></span><span>n</span><span> (О3)=</span><span>m</span><span>/ </span><span>M</span><span>= 72г:48г/моль=1,5моль</span>