Question

С 4 и 5 + С 0 и 5
Help

Answer 1

$C^m_n= \frac{n!}{m!*(n-m)!}$ ; 0!=1
$C^4_5+C^0_5= \frac{5!}{4!(5-4)!}+ \frac{5!}{0!(5-0)!} = \frac{1*2*3*4*5}{1*2*3*4*1} + \frac{1*2*3*4*5}{1*1*2*3*4*5} = 5+1=6$