Question

Докажите тождество: 9-p^2/3p+9*p^2/(3-p)^2+p/p-3=-p/3. Людиии,,, помогите прошу, пожалуйста!!!

Answer 1

$\frac{9- p^{2} }{3p+9}* \frac{p^{2}}{(3-p)^{2} } + \frac{p}{p-3}= - \frac{p}{3}$

$\frac{(3-p)(3+p)}{3(p+3)}* \frac{p^{2} }{(3-p)(3-p)}- \frac{p}{3+p} = \frac{p^{2} }{3(3-p)}- \frac{p}{3-p}= \frac{p^{2}-3p }{3(3-p)}= \frac{p(p-3)}{3(3-p)} =$$\frac{p(p-3)}{-3(p-3)}=- \frac{p}{3}$

$- \frac{p}{3} = -\frac{p}{3}$

Тождество верно.