Question

Lim x=3 4x^2 - 11x -3/ 3x^2 - 8x -310 баллов!!

Answer 1

4x^2-11-3 = (x-3)(4x+1)
D=121+4*3*4=169
x12=(11+-13)/8=3 -1/4
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3x^2-8x-3=(x-3)(3x+1)
D=64+4*3*3=100
x12=(8+-10)/6=3   -1/3

$\lim_{x \to 3} \frac{4x^2-11x-3}{3x^2-8x-3} = \lim_{x \to 3} \frac{(4x+1)(x-3)}{(3x+1)(x-3)} = \lim_{x \to 3} \frac{(4x+1)}{(3x+1)} = \frac{4*3+1}{3*3+1}= \frac{13}{10}$