Да, реакция этерификации с образованием сложного эфира.
C2H5OH+CH3COOH=CH3COOC2H5+H2O (в присутствии Н2SO4)
2СH3CH2COOH + Ba = (CH3CH2COO)2Ba + H2
2CH3CH2COOH + BaO = (CH3CH2COO)2Ba + H2O
2CH3CH2COOH + Ba(OH)2 = (CH3CH2COO)2Ba + 2H2O
2CH3CH2COOH + BaCO3 =(CH3CH2COO)2Ba + H2O + CO2
C2H5OH+O2=CH3COOH+H2O
CH3COOH+Cl2=CH2ClCOOH+HCl
CH2ClCOOH+NH3=CH2NH2COOH+HCl
CuO+H2SO4-->CuSO4+H2O
CuO+2H(+)+SO4(2-)-->Cu(2+)+SO4(2-)+H2O
CuO+2H(+)-->Cu(2+)+H2O
CuSO4+7H2O--->CuSO4+7H2O