1)12x32x=384x
2)18x35b=630b
A)(x^2)/x+3=(2x+3)/x+3, x≠-3
x^2=2x+3
x^2-2x-3=0
D=(-2)^2-4×1×(-3)=4+12=16
x1=(2-√16)/(2×1)=(2-4)/2=-2/2=-1
x2=(2+^16)/(2×1)=(2+4)/2=6/2=3
Ответ: x1=-1, x2=3
б)(2x)/(x+6)-(144)/(x-6)(x+6)=1
(2x(x-6)-144)/(x-6)(x+6)=1
2(x^2-6x-72)/(x-6)(x+6)=1
2(x^2+6x-12x-72)/(x-6)(x+6)=1
2(x(x+6)-12(x+6))/(x-6)(x+6)=1
2(x+6)(x-12)/(x-6)(x+6)=1
2(x-12)/(x-6)=1
2x-24=x-6
2x-x=-6+24
x=18
№330
а) (256-16)+(3+4)=247
б)а+98+49=147+а
№331
а)(13+65)-(11+54)=13
б) а+86-91= а+86-91
<span>2(x+2)-4(x-3)=5x+9
2х + 4 - 4х + 12 = 5х + 9
2х - 4х - 5х = 9 - 4 - 12
-7х = -7
7х = 7
х = 7 : 7
х = 1</span>