Question

25 баллов
Помогите, задание прикрепил

Answer 1

$-log_2(x^2+7x+10)\ \textgreater \ -log_24\\ log_2(x^2+7x+10)\ \textless \ log_24 \\ \begin{cases} x^2+7x+10\ \textgreater \ 0 \\ x^2+7x+10\ \textless \ 4 \end{cases} \ \textless \ =\ \textgreater \ \begin{cases} (x+2)(x+5)\ \textgreater \ 0 \\ x^2+7x+6\ \textless \ 0 \end{cases} \ \textless \ =\ \textgreater \ \\ \begin{cases} (x+2)(x+5)\ \textgreater \ 0 \\ (x+1)(x+6)\ \textless \ 0 \end{cases} \ \textless \ =\ \textgreater \ \begin{cases} x \in (- \infty; -5) \cup (-2; \infty); \\ x \in (-6; -1) \end{cases} =\ \textgreater \ \\ x \in (-6;-5) \cup (-2;-1)$
Ответ: (-6;-5)U(-2;-1)