<span>
</span>
y-x=14
x=-(-y+14)
x=y-14
<span>
(y-14)^2-3y^2=52
y^2-28y+196-3y^2-52=0
-2y^2-28y+196-52=0
-2y^2-28y+144=0
</span>
D=(-28)^2-4*(-2)*144=784+1152=1936
y1=(44-(-28))/(2*(-2))=-18
y2=(-44-(-28))/(2*(-2))=4
y-x=14
(-18)-x=14
x1=-32
4-x=14
x2=-10
Ответ: x1=-32; x2=-10; y1=-18; y2=4.
-3a² + b² = -3(-2)² + 5² = -3 · 4 + 25 = 25 - 12 = 13;
3х2+8х-3у2=3х2+(8х-3у)=3у2+5х2=8у-4х=4у2