Int dx / V(ax^2 + bx + c) = 1/V(a) * ln |2ax + b +2V(a) * V(ax^2 + bx + c)| + C
В нашем случае
Int
(от 0 до 1) dx / V(x^2 - 2x + 2) = ln |2x - 2 + 2V(x^2 - 2x + 2)| (от 0
до 1) = ln |2 - 2 + 2V(1 - 2 + 2)| - ln |0 - 2 + 2V(0 - 0 + 2)| =
= ln 2 - ln |2V(2) - 2| = ln (V(2) + 1)
2/7 :8 + 5/0,7 - 3/4 :21 = 7целых 1/7
1) 2/7 : 8 = 2/7 * 1/8=2/56=1/28
2) 5 : 7/10 = 5 * 10/7 = 50/7
3) 3/4 : 21 = 3/4 * 1/21=1/28
4) 1/28 + 50/7 = 1/28 + 200/28 = 201/28
5) 201/28 - 1/28 = 200/28 =50/7 = 7 целых 1/7
1080 .........................................
А)2/х=8/4
х=1
б) х/27=2/3
х=18
в)2/5=5х
х=0,08