2x - ay + bz
a = 3c
b = 14c^3
x = 5c^3 + 2
y = 6c^2 - c + 13
z = 5c - 1
2(5c^3 + 2) - 3c*(6c^2 - c + 13) + 14c^3*(5c - 1) =
= 10c^3 + 4 - 3c*6c^2 + 3c*c - 39c + 70c^4 - 14c^3 =
= 10c^3 + 4 - 18c^3 + 3c^2 - 39c + 70c^4 - 14c^3 =
= 70c^4 - 22c^3 + 3c^2 - 39c + 4
5x+3=27-3x
5x+3x=27-3
8x=24
x=24:8
x=3
{3x-13>0 ; {3х>133 \ :3 ; {х>13\3
<span>{25-4x>0 ; {4х<25 \ :4 ; {х<6,25
6,25>х>13\3</span>
ОДЗ 3-х>0,3-x≠1,7-x>0⇒x<3,x≠2,x<7⇒x∈(-≈;2) U(2;3)
1)0<3-x<1⇒-3<-x<-2⇒2<x<3⇒x∈(2;3)
7-x≥1⇒x≤6⇒x∈(-≈;6]
x∈(2;3)Ux∈(-≈;6]⇒x∈(2;3)
2)3-x>1⇒x<2⇒x∈(-≈;2)
7-x≤1⇒x≥6⇒x∈[6;≈)
x∈(-≈;2)Ux∈[6;≈)⇒нет решения
Ответ x∈(2;3)