224...............................
Ответ: 85679 + 85679 = 17
684259 деталь
684259 деталь
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1368518 изделие
В одном км, содержится 1000 метров, значит 7км080м = 7080 м
![S=\pi*R*l=\pi*R^2+\frac{1}{2}*(2R)*h](https://tex.z-dn.net/?f=S%3D%5Cpi%2AR%2Al%3D%5Cpi%2AR%5E2%2B%5Cfrac%7B1%7D%7B2%7D%2A%282R%29%2Ah)
![\pi*R*\sqrt{R^2+h^2}=\pi*R^2+R*h](https://tex.z-dn.net/?f=%5Cpi%2AR%2A%5Csqrt%7BR%5E2%2Bh%5E2%7D%3D%5Cpi%2AR%5E2%2BR%2Ah)
![\pi*\sqrt{R^2+h^2}=\pi*R+h](https://tex.z-dn.net/?f=%5Cpi%2A%5Csqrt%7BR%5E2%2Bh%5E2%7D%3D%5Cpi%2AR%2Bh)
![(\pi)^2*(R^2+h^2)=(\pi)^2*R^2+2*\pi*R*h+h^2](https://tex.z-dn.net/?f=%28%5Cpi%29%5E2%2A%28R%5E2%2Bh%5E2%29%3D%28%5Cpi%29%5E2%2AR%5E2%2B2%2A%5Cpi%2AR%2Ah%2Bh%5E2)
![h^2((\pi)^2-1)-2*\pi*R*h=0](https://tex.z-dn.net/?f=h%5E2%28%28%5Cpi%29%5E2-1%29-2%2A%5Cpi%2AR%2Ah%3D0)
![h=\frac{2*\pi*R}{(\pi)^2-1}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B2%2A%5Cpi%2AR%7D%7B%28%5Cpi%29%5E2-1%7D)
обьем равен
![V=\frac{1}{3} \pi R^2h=\frac{1}{3}*R^2*\frac{2*\pi*R}{(\pi)^2-1)}=\\\\\frac{2*\pi*R^3}{3*((\pi)^2-1)}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D+%5Cpi+R%5E2h%3D%5Cfrac%7B1%7D%7B3%7D%2AR%5E2%2A%5Cfrac%7B2%2A%5Cpi%2AR%7D%7B%28%5Cpi%29%5E2-1%29%7D%3D%5C%5C%5C%5C%5Cfrac%7B2%2A%5Cpi%2AR%5E3%7D%7B3%2A%28%28%5Cpi%29%5E2-1%29%7D)
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A4
Обьем призмы равен V=SH
поэтому следуя условию получаем
![h_4>h_3>h_2>h_1](https://tex.z-dn.net/?f=h_4%3Eh_3%3Eh_2%3Eh_1)
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A3.
![d^2=3a^2;](https://tex.z-dn.net/?f=d%5E2%3D3a%5E2%3B)
ребро куба равно
![a=\frac{d\sqrt{3}}{3}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bd%5Csqrt%7B3%7D%7D%7B3%7D)
Обьм куба равен
![V=a^3=\frac{d^3\sqrt{3}}{9}](https://tex.z-dn.net/?f=V%3Da%5E3%3D%5Cfrac%7Bd%5E3%5Csqrt%7B3%7D%7D%7B9%7D)
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A2
так как 21:5=4(ост1)
27:5=5(ост 2)
9:5=1(ост 4)
то кубиков со стороной 5 может влезть не более чем 4*5*1=20
ответ: 20 кубиков