Как мне кажется, должно быть так:) и нет никаких коэффициентов:) удачи))
3СаCl2 + 2Al = 3Ca + 2AlCl3
<span>По уравнению - из 196 кг хлорида получается 196*40/111 = 70,6 кг кальция (теоретический выход) . Практический выход 70,6*0,88 = 62,1 кг.</span>
KCl, PbSO4, NaF, NaS, Mg3(PO4)2, ZnCl2, Al(NO3)3
2SO2+O2=2SO3
2Fe+ 3CL2=2FeCL3
N2+3H2=2NH3
Zn+2HCL=ZnCL2+H2
<span>фосфор <span>1s</span></span>² <span><span>2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>³<span><span><span>
</span></span></span><span>фтор <span>1s</span></span>² <span><span>2s</span></span>² <span><span>2p</span></span>⁵<span><span><span>
</span></span></span><span>аргон <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁶<span><span><span>
</span></span></span><span>алюминий <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>¹<span><span><span>
</span></span></span><span>сера <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁴<span><span><span>
</span></span></span><span>калий <span>1s</span></span>²<span><span> 2s</span></span>²<span><span> 2p</span></span>⁶<span><span> 3s</span></span>²<span><span> 3p</span></span>⁶ <span><span>4s</span></span>¹
