<span>ну, например так</span>
<span>CuSO</span><span>₄</span> +2<span>KOH</span> = <span>Cu</span>(<span>OH</span>)<span>₂↓</span> + <span>K</span><span>₂</span><span>SO</span><span>₄ - молекулярное</span>
<span>Cu</span><span>²⁺ + </span><span>SO</span><span>₄²⁻ + 2</span><span>K</span><span>⁺ + 2</span><span>OH</span><span>⁻ = </span><span>Cu</span><span>(</span><span>OH</span><span>)₂↓ + 2</span><span>K</span><span>⁺ +</span><span>SO</span><span>₄²⁻ - полное ионное</span>
<span>Cu</span><span>²⁺ +</span><span> 2</span><span>OH</span><span>⁻</span> = <span>Cu</span><span>(</span><span>OH</span><span>)₂↓ - сокращенное ионное</span>
<span> </span>
Решение!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Ответ:
Al2O3+6HNO3=2Al(NO3)3+H2O
2CO+O2=2CO2
2HCl+2Mg=2MgCl2+H2
2K+Cl=2KCl
P2O5+H2O=2H3PO4
2AlCl3+3Ca(OH)2=2Al(OH)3+3CaCl2
Ответ:
Объяснение:
2FeCl2 + Cl2 = 2FeCl3
Fe(+2) -1e = Fe(+3) 2 ок-ие
в-ль
Cl2(0) +2e = 2Cl(-) 1 в-ие
ок-ль