2 so2 + o2 --- 2 so3
n(so2)= 9,6:64=0,15 моль
n(so2)=n(so3)= 0,15 моль
w(выхода)=(11,25:12)*100%=93,75%
FeSO4 + 2KOH = Fe(OH)2 + K2SO4
n(FeSO4) = 1/2n(KOH) = n(Fe(OH)2) = 0.16/2 = 0.08 моль
m(Fe(OH)2) = 0.08 моль х 90 = 7.2 г
Ответ: 7.2г
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А
1)CaC2 + H2O = C2H2 + Ca(OH)2
2)C2H2 + H2 = C2H4
3)C2H4 + H2O = C2H5OH
4)C2H5OH + CuO = CH3-C(=O)(-H)
Б.
1)2CH4 = C2H2
2)C2H2 + H2O = CH3-C(=O)(-H)
4)CH3-C(=O)(-H) + H2 = C2H5OH
5)C2H5OH + CuO = CH3-C(=O)(-H)