Cos(x+3π)=0
x+3π=π/2+πn, n∈Z
x=π/2-3π+πn, n∈Z
x= -5π/2 +πn, n∈Z
-6x^3-3(x^3-1)²=
= -6x^3-3(x^6-2x^3+1)=
= -6x^3-3x^6+6x^3-3=
= -3x^6-3= -3(x^6-1)=
= -3(x^3-1)(x^3+1)=
= -3(x-1)(х²+x+1)(x+1)(х²-x+1)
значок ^ обозначает в степени
1.=-15,92
2.=61.5
3.=-3,441
4.=144,03