<span><span>Ca<span>(OH)</span>2</span>+<span>2<span>HCl</span></span> → <span>CaCl2</span>+<span>2<span>H2<span>O
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Запишем уравнение реакции
NH₄Cl + NaOH = NaCl + NH₃ +H₂O
составим пропорцию
25 г - 100%
х г - 40%
100х = 40 * 25
100х = 1000
х = 10
NaOH = 10 г
10 - 40
х - 22,4
40х = 224
х = 5,6 л.
Ответ. V(NH₃) = 5,6 л.
<span>Pb(NO3)2
Mr(</span><span>Pb(NO3)2)=85+14*2+16*6=209
w(Pb)=85/209*100\%=41\%
w(N2)=28/209*100\%=13\%
w(O2)=96/209*100\%=46\%
</span>
2Ca+O2=2CaO
CaO+3C=CaC2 +CO
Ca+H2=CaH2
CaO+H2O=CA(OH)2
Ca(OH)2+H2CO3= CaCO3+2H2O
CaCO3+CO2+H2O=Ca(HCO3)2
Ca(HCO3)2= CaCO3+CO2+H2O
CaCO3+2HCL= CaCL2+H2O+CO2
CO2+CaO=CaCO3
Ca+2C=CaC2
CaC2+2H2O=Ca(OH)2+C2H2
Ca(OH)2+ CO2=CaCO3+H2O
Ca+H2CO3=CaCO3+H2
CaCO3=CaO+CO2