В приложении
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A+b=(-2+2;7+7;-4+3)=(0;14;-1)
(a+b)c=0*3+14*7-1*2=96
S = n*(n+1)/2 = 200*(200+1)/2 = 20100
<span>Находим сумму арифметической прогрессии а1=20 и d=20 от 20 до 200, где а10 = 200 </span>
<span>s = (a1+a10)*10/2 = (20+200)*10/2 = 1100 </span>
<span>Ответ: </span>
<span>S - s = 20100 - 1100 = 19000</span>
1 1*√3 √3
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√3 √3 *√3 3
√10 + 8 (√10 +8)(√10 +8) (√10+8)² 10+16√10 +64 -37-8√10
``````````` = ````````````````````````` = `````````` = ```````````````````` = ``````````
√10 - 8 (√10 -8)(√10+8) 10 - 64 - 54 27
1 5+√5 5+√5 5+√5
````` = ``````````````````` = ``````````` = ````````````
5-√5 (5- √5)(5+√5) 25 -5 20