(1/3)^x = 27
(1^x) = 27 * (3^x)
In(1^x) = In(27*(3^x))
In(3x) + 3In(3) = 0
x = -3
<span> 2х+5/х²+х - 2/х- 3х/х+1=0
</span> 2х+5- 2(х+1) - 3х²/х(х+1)=0
2х+5-2х-2-3х²/х(х+1)=0
3-3х²/х(х+1)=0
3(1-х)(1+х)/х(х+1)=0
3-3х/х=0
3-3х=0
-3х=-3
х=1
4(2x²-4x+3)-3x(5-4x)=8x²-16x+12-15x+12x²=20x²-31x+12
(3х-5у)^3.....
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