<span>а) x²y-bx²-axy+abx = (</span><span><span>x²y-bx²)-(axy-abx)=х²(y-b) -ax(y-b)=(y-b)(x²-ax)=(y-b)·x·(x-a)
</span>б) ac²-ad-bc²+cd+bd-c³=(</span><span>ac²-ad)-(bc²-bd)-(c³-cd)=a(c²-d)-b(c²-d)-c(c²-d)=</span>(c²-d)·(a-b-c) - только два множителя?
F'(x) = [(2 +√ x)'(2 - √ x) - (2 + √ x)(2 - √ x)'] / (2 - √ x)² =
= [(1/2√ x)(2 - √ x) - ( 2 + √ x)( - 1/2√ x)] / (2 - √ x)² =
= [1/2√ x (2 - √ x + 2 + √ x)] / (2 - √ x)² = (2/√ x) / (2 - √ x)² = 2/ [√ x(2 - √ x)²]
2*(a²-6ab+9b²) + 24ab = 2a²-12ab+18b² + 24ab = 2a²+12ab+18b²
Если а=√45, b=√5, то 2a²+12ab+18b²= 2*√45²+12*√45*√5+18*√5²)= 2*45+12*15+18*5)= 90+180+90=360
-2x(x-4)=0
-2x²+8x=0 /-1
2x²-8x=0
x(2x-8)=0
x=0 или 2x-8=0
x=8/2
x=4