а)<span>2Ca + O2 = 2CaO</span>
<span>б)<span>2Na + 2H2O = 2NaOH + H2</span></span>
<span><span>в)<span>Cu(OH)2 = CuO + H2O</span></span></span>
<span><span><span>г)<span>2LiOH = Li2O + H2O</span></span></span></span>
<span><span><span><span>д)<span>Mg + H2SO4 = MgSO4 + H2</span></span></span></span></span>
<span><span><span><span><span>е)<span>Zn + CuSO4 = ZnSO4 + Cu</span></span></span></span></span></span>
<span><span><span><span><span><span>ж)-</span></span></span></span></span></span>
LiBr
Связь ионная
............................
дано
m(ppa KOH) =700 g
W(KOH) = 8%
-----------------------
n(K)-?
m(KOH) = 700 * 8% / 100% = 56 g
2K+2H2O-->2KOH+H2
M(KOH) = 56 g/mol
n(KOH) = m/M = 56 / 56 = 1 mol
2n(K) = 2n(KOH) = 1 mol
n(KOH) = 1 mol
ответ 1 моль
3Ca+N₂→Ca₃N₂
Тут ОВР не нужно, коэфиценты и так легко расставить
Дано:
V(C₂H₄) = 60л
+O₂
Найти:
V(O₂)
Решение:
1С₂H₄ + 3O₂ → 2CO₂ + 2H₂O
V(O₂) = (60×3)÷1 = 180л
Ответ: V(O₂) = 180л