Fe2O3+3H2=2Fe+3H2O
по уравнению реакции 3моль Н2-2 моль Fe
2 моль Н2-х моль Fe x=1,33моль
m(Fe)=1,33*56г\моль=74.48г
прак. выход 74,48г*0,95=70,76г
A-FeCl2
B-HCl
C-FeS
D-NaCl
i-NH4Cl
<span>(NH</span>4<span>)</span>2<span>SO</span>4<span> + 2KOH -> K</span>2<span>SO</span>4<span> + 2NH</span>3<span> + 2H</span>2<span>O</span>
<span>2NH</span>4+<span> + SO</span>42-<span> + 2K</span>+<span> + 2OH</span>-<span> -> 2K</span>+<span> + SO</span>42-<span> + 2NH</span>3<span> + 2H</span>2<span>O</span>
<span>2NH</span>4+<span> + 2OH</span>-<span> -> 2NH</span>3<span> + 2H</span>2<span>O</span>
<span>NH</span>4+<span> + OH</span>-<span> -> NH</span>3<span> + H</span>2<span>O</span>