СnH(2n-6) + Br2 -(FeBr3)-> CnH(2n-5)Br + HBr
m теор(CnH(2n-5)Br)=35,82/0,75=47,76г
28,8/(12n+2n-6) = 47,76/(12n+2n-5+80)
28,8*(14n+75) = 47,76/(14n-6)
403,2n+2160 = 668,64n-286,56
265,44n = 2446,56
n = 9
C9H13 - фенилпропан
5N2O + 3H2SO4 + 2KMnO4 = 10NO + 2MnSO4 + K2SO4 + 3H2O
2NaCl+H2SO4=(t) Na2SO4 + 2HCl
n(NaCl)=
![\frac{214}{58,5} =3,658](https://tex.z-dn.net/?f=+%5Cfrac%7B214%7D%7B58%2C5%7D+%3D3%2C658)
моль
n(HCl)=
![\frac{500*0,2606}{36,5} =3,5699](https://tex.z-dn.net/?f=+%5Cfrac%7B500%2A0%2C2606%7D%7B36%2C5%7D+%3D3%2C5699)
моль
Составим пропорцию:
3,5699------х%
3,658-------100% выход (где х-выход HCl)
х=
![\frac{3,5699*100}{3,658} =97,59](https://tex.z-dn.net/?f=+%5Cfrac%7B3%2C5699%2A100%7D%7B3%2C658%7D+%3D97%2C59)
%
Ответ: 97,59%
2Са+О2=2СаО
СаО+Н2О=Са(ОН)2
Са(ОН)2+2HCl=CaCl2+2H2O