<em>М( Н2SO4)= 1*2+32+16*4=98 г/моль</em>
<em><u>Ответ: М( Н2SO4)=98 г/моль</u></em>
<span>C</span>2<span>H</span>5<span>OH</span><span> + </span><span>CH</span>3<span>COOH</span><span> =</span><span> </span><span>CH</span>3<span>COOC</span>2<span>H</span>5<span> (запах) + </span><span>H</span>2<span>O</span>
Реакции прикладываю во вложении