Дано
m = 16 г
w(примесей) = 6.25% = 0.0625
Решение
w(Al2S3) = 1 - w(примесей) = 1 - 0.0625 = 0.9375
m(Al2S3) = mw(Al2S3) = 16 * 0.9375 = 15 г
n(Al2S3) = m(Al2S3) / M(Al2S3) = 15 / (2 * 27 + 3 * 32) = 15 / 150 = 0.1 моль
Al2S3 + 6H2O = 2Al(OH)3 + 3H2S
n(Al(OH)3) = 2n(Al2S3) = 2 * 0.1 = 0.2 моль
m(Al(OH)3) = n(Al(OH)3)M(Al(OH)3) = 0.2 * (27 + 3 * 16 + 3 * 1) = 0.2 * 78 = 15.6 г
Ответ: 15.6 г
Ответ на данный пример -102
M(раствора) =3000 см3* 1.112г/см3=3336г
m(соли) =3336*0.05=166.8г
2Ch2=ch2 + O2 - > 2CH3-CHO
CH3-CHO + H2 - > C2H5 OH
C2H5-OH + CuO -> CH3-CHO + Cu + H2O
Ch3-Cho + Ag2O -> Ch3Cooh + 2Agv
CH3COOH + HO-C2H5 -> CH3COO-C2H5 + H2O
В) S -> H₂S -> K₂S
S + H₂ -> H₂S
H₂S + 2KOH -> K₂S + 2H₂O
г) HBr -> H₂ -> NH₃
2HBr + Mg -> H₂ + MgBr₂<span>
</span>H₂ + KNO₃ -> NH₃ + KOH + 2H<span>₂</span>O