1) 2CH3OH + 2Na = 2CH3ONa + H2
2Na + 2H2O = 2NaOH + H2
2) Al2O3 + Ba(OH)2 (t)= Ba(AlO2)2 + H2O
M(Ba(AlO2)2) = 255 г/моль
M(Al) = 27 г/моль
W(Al) = 54/255 = 0.212
Во вложении:
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C, Si, Ge, Sn,Pb........