-6/17<x<-5/17
-12/34<x<-10/34
-24/68<x<-20/68
х=-23/68
х=-22/68
х=-21,68
1) 7÷10= 0,7
2)2÷15 =0,1(3)
3)11÷30=0,30(6)
4)0,7+0,1(3)+0,30(6)=1,10(9)
1) -0,8*(-4,5)=3,6
2) 2,4+3,6=6
3) (-14,4):6=(-2,4)
4) (-2,4):(-0,15)=16
<span>г)-6/7*(-2 13/18)=6/7* 49/18=1/7* 49/3=1/1*7/3=7/3=2 1/3
д)3 3/9:(-2 2/3)=- 30/9 : 8/3=-30/9* 3/8=-15/9*3/4=-15/3*1/4=-15/12=-5/4=-1 1/4=-1,25
.. 2. 4/29=0,14 и 2 9/34= 2,26
3. 8/27=0,30 и 1 3/28=1,11</span>
<span><span>Всё, что получилось:
1) f′</span>(x)=<span><span>(12+6⋅x−2⋅<span>x^5</span>)</span>′</span>=</span><span><span><span>(12+6⋅x)</span>′</span>−<span><span>(2⋅<span>x^5</span>)</span>′</span>=</span><span><span><span>(6⋅x)</span>′</span>−2⋅<span><span>(<span>x^5</span>)</span>′</span>=</span><span>6−10⋅<span>x^4
</span></span>
<em><u>Ответ: </u></em><span><em><u>f′</u></em><em><u>(x)=6−10⋅</u></em><span><em><u>x^4
</u></em><em><u /></em>2) -
<em><u>
</u></em><em><u /></em><u />3) -
<em><u>
</u></em><em><u /></em><u />4) </span></span><span>f(x)=4^√x=</span>f<span>′(x)=<span><span>(<span>4^√x</span>)</span>′</span>=</span><span><span>4^√x</span>⋅ln<span>(4)</span>⋅<span><span>(√x)</span>′</span>=(</span><span><span><span>4^√x</span>⋅ln<span>(4))/(</span></span><span>2⋅<span>√x)
</span></span></span>
<em><u>Ответ: f(x)=(4^√x⋅ln(4))/(2⋅√x)</u></em>