СH4 + Cl2 = CH3Cl + HCl
2CH3Cl + 2Na = C2H6 + 2NaCl
C2H6 + Br2 = C2H5Br + HBr
C2H5Br + C4H9Br + 2K = C6H14 + 2KBr
H₂ + Cl₂ = 2HCl
6HCl + 2Al = 2AlCl₃ + 3H₂
AlCl₃ + 3KOH = Al(OH)₃ + 3KCl
2Al(OH)₃ = Al₂O₃ + 3H₂O
2Al₂O₃ + 3C = 4Al + 3CO₂
1) H₂SO₄ + 2LiOH = Li₂SO₄+2H₂O
2) n(LiOH)=m/Mr=4.8/24=0.2 моль
3) n(H₂SO₄)=0.5n(LiOH)=0.5*0.2=0.1моль
4) m(H₂SO₄)=n(H₂SO₄)*Mr(H₂SO₄)=0.1*98=9.8г
Дано
w(N) = 82.36% = 0.8236
NxHy
Решение
w(H) = 1 - w(N) = 1 - 0.8236 = 0.1764
w(N) = xAr(N) / (xAr(N) + yAr(H)) = 14x / (14x + y) = 0.8236
14x = 0.8236(14x + y)
14x = 0.8236(14x + y)
14x = 11.5304x + 0.8236y
2.4696x = 0.8236y
3x = 1y
x : y = 1 : 3
NH3
Ответ: NH3