2al+3h2so4=al2(so4)3+3H2
находим чистого алюминия
100\%-6\%=94\%
94*5/100=4,7г(AL)
n(al)=4.7/27=0.17моль
n(h2)=0.17*3/2=0.261
V(H2) 0.261*22.4=5.84 литров
2NaOH+H2SO4=Na2SO4+2H2O
n=m/M
n(NaOH)=16/40=0.4
n(NaOH):n(H2SO4)
2:1
n(H2SO4)=0.2
m=n*N
m(H2SO4)=0.2*98=19.6гр
m(р-ра)(H2SO4)=19.6*100%/10%=196г
V=m/p
V(H2SO4)=196/1.07=183.18см³
Ca3(PO4)2 + 5C + 3SiO2 = 2P + 3CaSiO3 + 5CO
4P+5O2=2P2O5
P2O5+3H2O=2H3PO4
NaOH + H3PO4(избыток) = NaH2PO4 + H2O
NaH2PO4 + NaOH = Na2HPO4 + H2O
Na2HPO4 + NaOH = Na3PO4 + H2O
2Na3PO4+3Сa(OH)2=Ca3(PO4)2+6NaOH