Дано
AlxOy
w(Al) = 53.8% = 0.538
w(O) = 46.2% = 0.462
Решение
w(Al) = xAr(Al) / (xAr(Al) + yAr(O)) = 27x / (27x + 16y) = 0.538
27x / (27x + 16y) = 0.538
27x = 0.538(27x + 16y)
27x = 14.526x + 8.608y
12.474x = 8.608y
1.5x = 1y
3x = 2y
x : y = 2 : 3
Al2O3
Ответ: Al2O3
Mr(CaCO3) = 40+12+16*3 = 100
Mr(MgCl2) = 24 + 35,5*2 = 95
Mr(Fe2(SO4)3) = 56*2 +32*3 + 16*12 =342