<span>6NaOH + P2O5 = 2Na3PO4 + 3H2O
</span><span>HNO3 + Fe2O3 = 2 Fe(NO3)3 + 3H2O
</span>Cu(OH)2 + 2KOH = K2CuO2 + 2H2O
<span>Mg(OH)2 + BaCl2 = </span><span>MgCl2 + Ba(OH)2
</span><span>2FeSO4 + Pb(NO3)2 = 2FeNO3 + Pb(SO4)<span>2
</span></span><span>BaCl2 + Na2So4 = BaSo4 + 2 NaCl
</span><span>Al2(SO4)3 + 3BaCl2 = 2AlCl3 + 3BaSO4
</span><span>Cu(OH)2 = CuO+H2O
</span><span>ZnCl2 + 2AgNO3 = Zn(NO3)2 + 2AgCl</span>
1) 2Na + О2 = 2 Na2O
Na2O + H2O = 2 NaOH<span>
</span>2NaOH + CuCl2 = Cu(OH)2 + 2NaCl
<span>Cu(OH)2 = CuO + H2O
CuO +Ca = CaO + Cu
2) Ba + O = BaO
BaO + H2O = Ba(OH)2
Ba(OH)2 + 2HCl = BaCl2 + 2H2O
3) 4P + 5O2 = 2P2O5
P2O5 + 3H2O = 2H3PO4
H3PO4 + 3KOH = K3PO4 + 3H2O
4) S + O2 = SO2
2SO2 + O2 = 2SO3
SO3 + H2O = H2SO4
5) C + O2 = CO2
CO2 + H2O = H2CO3</span>
.............................................
M(MgSO4)=(15%* 240 г )/100%=36 гm(H2O)=m(р-р)-m(MgSO4)=240 г-3 6 г=204 гV(H2O)=204 г/1(г/мл)=204 мл <span>ответ:для приготовления 240 г 15% раствора понадобится 204 мл воды и 36 г соли
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