X²-4=2x-1
x²-2x-3=0
D=4+12=16=4²
x1=(2+4)/2 = 6/2 =3
x2=(2-4)/2 = -2/2=-1
(-1;3)∫ (x²-2x-3) dx = x³/3 - x²-3x | (-1;3) = 27/3 - 9 -9 - (-1/3-1+3) =
= 9-9-9+1/3+1-3 = -11+1/3= -10 3/3+1/3 = -10 2/3 отриц площадь не может быть тогда ⇒ 10 2/3
((16x^2 - 1) - (6x^2 - 4x - 2)(16x^2 - 1) - (6x^2 - 4x - 2)(16x^2 - 1) )-
- (6x^2 - 4x - 2) = (16x^2 - 1)(1 - 6x^2+4x + 2- 6x^2 + 4x + 2) - (6x^2 - 4x-2)=
= (16x^2 - 1)(- 12x^2+ 8x + 5) - (6x^2 - 4x - 2) = -192x^4 + 128x^3+80x^2 +
+ 12x^2 - 8x - 5 - 6x^2 + 4x + 2 = - 192x^4+ 128x^3 + 86x^2 - 4x- 3
При x = 3,7:
- 192*187,4161 + 128*50,653 + 86*13,69 - 14,8 - 3 =
= - 35983,891 + 6483,584 + 1177,34 - 17,8 =
= - 29500,307 + 1159,54 = - 28340,767
Как-то так................