CUSO4+2NaOH = Cu (OH)2+Na2SO4
<span>K</span>⁺<span>Mn</span>⁺⁷<span>O</span>₄⁻²<span> +3Fe</span>⁺²<span>S</span>⁺⁶<span>O</span>₄⁻²<span> + 2H</span>₂⁺<span>O</span>⁻²<span> ----> Mn</span>⁺⁴<span>O</span>₂⁻²<span> + 3Fe</span>⁺³<span>O</span>⁻²<span>H</span>⁺¹<span>S</span>⁺⁶<span>O</span>₄⁻²<span> + K</span>⁺¹<span>O</span>⁻²<span>H</span>⁺¹
<span>Mn</span>⁺⁷ + 3e=Mn<span> </span>⁺³ 1 ок-ль, вос-ние
Fe⁺² - 1e= Fe⁺³ 3 ок-ль, вос-ние