В пергаманте калия,кислорода 40,5\%
2H2O = 2H2 + O2
m(H2O) = 1.8 g
M(H2O) = 16 + 2 * 1 = 18 g/mol
n(H2O) =m/M = 1.8 / 18 = 0.1 mol
n(O2) = n(H2O) / 2 = 0.05 mol
V(O2) = n*Vm = 0.05 * 22.4 = 1.12 l
1) С + О2 = СО2
<span> S -> SO2 -> H2SO3 -> K2SO3</span>