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4 года назад

5

Вычислите значения выражения: arcsin1 + arccos0 - 2arctg0

1 ответ:

благославленная [7]4 года назад

0 0

<span>arcsin1 + arccos0 - 2arctg0=π/2 + π/2 -2*0 = π</span>

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Помогите срочно нужно пожалуйста

Света Солнышкина [4.8K]

2'=0.
х'=1.
(3х)'=3.
(Х^3)= 3х^2.
(4х^4+4)'=16х^3.
(1/2•х^4+2/3•х^3+2х^2+2)'=2х^3+2х^2+4х.
((3х^3-2)(2х^2-3))'=9х^2•(2х^2-3)+4 х •(3х^3-2).
((3х^2)/(х+2))'=(6х•(х+2)-3х^2)/(х+2)^2=3х/(х+2).

0 0

3 года назад

Из данных линейных функций выберете ту, которая является прямой пропорциональностью. 1) y=-x+1 2) y=0,05x 3) y=2x-2 4) y=1И напи

Анастасия Жидко [2]

Прямая пропорциональность: у=0,05х, поскольку задается формулой у=кх, где к = 0,05

0 0

4 года назад

A2/12b:ab/36 Помогите

Shveik2010

A²/12b : ab/36=
a²/12b * 36/ab=
3а / b²

сократили
36:12=3;
а²:а=а

b*b=b²

0 0

4 года назад

Помогите пожалуйста решить, 1 задание! Заранее спасибо)

тихон иваныч [21]

<span>Дана система ур-ний</span>
<span /><span><span><span><span><span><span>3</span><span>x</span><span>+</span><span>y<span /></span><span>=</span><span>2</span></span><span /></span></span><span /></span><span>3x+y=2</span></span>
<span /><span><span><span><span><span><span>2</span><span>x</span><span>−</span><span>y<span /></span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>2x−y=3</span></span>

<span>Из 1-го ур-ния выразим x</span>
<span /><span><span><span><span><span><span>3</span><span>x</span><span>+</span><span>y<span /></span><span>=</span><span>2</span></span><span /></span></span><span /></span><span>3x+y=2</span></span>
<span>Перенесем слагаемое с переменной y из левой части в правую со сменой знака</span>
<span /><span><span><span><span><span><span>3</span><span>x</span><span>=</span><span>−</span><span>y<span /></span><span>+</span><span>2</span></span><span /></span></span><span /></span><span>3x=−y+2</span></span>
<span /><span><span><span><span><span><span>3</span><span>x</span><span>=</span><span>−</span><span>y<span /></span><span>+</span><span>2</span></span><span /></span></span><span /></span><span>3x=−y+2</span></span>
<span>Разделим обе части ур-ния на множитель при x</span>
<span /><span><span><span><span><span><span><span><span><span><span>3</span><span>x</span></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span>1</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span><span>(</span><span>−</span><span>y<span /></span><span>+</span><span>2</span><span>)</span></span></span><span /></span></span><span /></span><span>3x3=13(−y+2)</span></span>
<span /><span><span><span><span><span><span>x</span><span>=</span><span>−</span><span><span><span><span>y<span /></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>+</span><span><span><span><span>2</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>x=−y3+23</span></span>
<span>Подставим найденное x в 2-е ур-ние</span>
<span /><span><span><span><span><span><span>2</span><span>x</span><span>−</span><span>y<span /></span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>2x−y=3</span></span>
<span>Получим:</span>
<span /><span><span><span><span><span><span>−</span><span>y<span /></span><span>+</span><span>2</span><span><span><span>(</span></span><span>−</span><span><span><span><span>y<span /></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>+</span><span><span><span><span>2</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span><span>)</span></span></span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>−y+2(−y3+23)=3</span></span>
<span /><span><span><span><span><span><span>−</span><span><span><span><span><span>5</span><span>y<span /></span></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>+</span><span><span><span><span>4</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>−5y3+43=3</span></span>
<span>Перенесем свободное слагаемое 4/3 из левой части в правую со сменой знака</span>
<span /><span><span><span><span><span><span>−</span><span><span><span><span><span>5</span><span>y<span /></span></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span>5</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>−5y3=53</span></span>
<span /><span><span><span><span><span><span>−</span><span><span><span><span><span>5</span><span>y<span /></span></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span>5</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>−5y3=53</span></span>
<span>Разделим обе части ур-ния на множитель при y</span>
<span /><span><span><span><span><span><span><span><span><span><span>−</span><span>1</span><span><span><span><span>5</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>y<span /></span></span><span /></span><span><span><span>−</span><span><span><span><span>5</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span><span><span /><span /></span></span></span><span>=</span><span>−</span><span>1</span></span><span /></span></span><span /></span><span>−153y−53=−1</span></span>
<span /><span><span><span><span><span><span>y<span /></span><span>=</span><span>−</span><span>1</span></span><span /></span></span><span /></span><span>y=−1</span></span>
<span>Т.к.</span>
<span /><span><span><span><span><span><span>x</span><span>=</span><span>−</span><span><span><span><span>y<span /></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>+</span><span><span><span><span>2</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>x=−y3+23</span></span>
<span>то</span>
<span /><span><span><span><span><span><span>x</span><span>=</span><span>−</span><span><span><span><span><span>−</span><span>1</span></span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span><span>+</span><span><span><span><span>2</span><span /></span><span><span>3</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>x=−−13+23</span></span>
<span /><span><span><span><span><span><span>x</span><span>=</span><span>1</span></span><span /></span></span><span /></span><span>x=1</span></span>

<span>Ответ:</span>
<span /><span><span><span><span><span><span>x</span><span>=</span><span>1</span></span><span /></span></span><span /></span><span>x=1</span></span>
<span /><span><span><span><span><span><span>y<span /></span><span>=</span><span>−</span><span>1</span></span><span /></span></span><span /></span></span><span>
</span>

0 0

3 года назад

3 (⁴√6)⁴ найдите значение выражения

Макс Ефимов [6]

Объяснение:

Если правильно пример понял, то ответ 18

0 0

4 года назад

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